
What is the difference between \dfrac and \frac? - TeX
Sep 27, 2013 · The title says it all, both \dfrac {a} {b} and \frac {a} {b} make fractions, so what is the difference between the two?
How to get a little frac - TeX - LaTeX Stack Exchange
Oct 8, 2010 · I am wondering how to make a fraction in LaTeX small enough to fit on a line, or at least just a little larger. I could have sworn I had seen this before but I just cannot find it. In …
Practical consequences of using \over vs. \frac? - TeX
This question explains the difference between \\over and \\frac and it seems as though the most experienced members unanimously agree that \\over is inferior (if not something to be outright …
math mode - How to do fractions - TeX - LaTeX Stack Exchange
Welcome to TeX.SX! Your question is basically about mathjax usage in websites (such as Math.SE), but fortunately, \frac or \dfrac command (for 'better' fractions) work with mathjax
Elegant fractions in one line - TeX - LaTeX Stack Exchange
It is nearly always best to use the slashed form for fractions in the text: \documentclass{article} \begin{document} \( x_F \equiv p_z^{}/p^{\mathrm{MAX}}_z = p_z/(\sqrt{s}/2) = 2p_z/\sqrt s \) …
Fractions with large elements - TeX - LaTeX Stack Exchange
With amsmath or mathtools you can write dfrac instead of frac, but since dfrac is used for inline fractions, it won't change anything for you in math environments. My workaround is using …
fractions - When to use \tfrac? - TeX - LaTeX Stack Exchange
Dec 8, 2016 · When should I use \\tfrac in formulas? I normally use it in power series, but are there other cases where it looks better with \\tfrac instead of a full size fraction? Are there any …
What is the difference between \over and \frac? - TeX
The command \over is a so-called "primitive" command that's available in Plain TeX and in LaTeX. \frac is a LaTeX-only command that builds on the \over macro to provide something …
How to integrate $\frac {1} {\sqrt {1+x^2}}$ using substitution?
So $\sqrt {1+x^2}=\frac {1} {2}\left (t+\frac {1} {t}\right)$. That was the whole point of the substitution, it is a rationalizing substitution that makes the square root simple.
Simplify $\frac {\frac {1} {x-1} + \frac {1} {x^2-1}} {x-\frac 2 {x + 1}}$
First recall that \ [ \frac {a} {b} \pm \frac {c} {d} =\frac {ad \pm cb} {bd} \] And \ [ \frac {\frac {a} {b}} {\frac {c} {d}} =\frac {ad} {bc} \] Now just simplify ...