Two of the terms involve \(x\) and two involve \(y\). Now we can combine the \(x\) terms and combine the \(y\) terms to get \(3x + 2y\).

\(\frac{{{a^2}b}}{{a{b^2}}} = \frac{{a \times a \times b}}{{a \times b \times b}}\) Since a and b are both factors, cancel this fraction by dividing by both a and b ...

expression let's say we have four times the quantity x minus y whatever X and Y are and then plus one and then I'm going to give you as a kind of like part of the problem that X is equal to negative 2 ...